3.66x^2+x-2=0

Solution for 3.66x^2+x-2=0 equation:

3.66x^2+x-2=0

a = 3.66; b = 1; c = -2;
Δ = b2-4ac
Δ = 12-4·3.66·(-2)
Δ = 30.28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{30.28}}{2*3.66}=\frac{-1-\sqrt{30.28}}{7.32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{30.28}}{2*3.66}=\frac{-1+\sqrt{30.28}}{7.32}
$